Ok problem 100 pg 518 I even tried looking this up online.....bad idea! I do not get what is supposed to be Po/P I have 10029=(30T+8000)ln(Po/P) My assumption is that the 22cm should be in the equation like this 10029=(30T-8000)ln(22/P) But I am not sure.
Don't worry about the table thing, just do what you know. As far as #100 goes, I am surprised you didn't discover this when you looked it up online, you maybe didn't know what to look for. In the problem we have two unknowns, T and Po. Obviously, we can't solve if we don't know one of those (since we are solving for T, we need to know Po. Po is the same universally, it is the Barometric pressure at sea level and is the same world wide. If you look on page 500, you will discover that the book states this to be 76cmHg. And that is what it will always be for all barometric pressure problems. So, just plug 76 in for Po and solve. THis should make the problem much easier.. P = 22 by the way.
Ok problem 100 pg 518
ReplyDeleteI even tried looking this up online.....bad idea!
I do not get what is supposed to be Po/P
I have 10029=(30T+8000)ln(Po/P)
My assumption is that the 22cm should be in the equation like this
10029=(30T-8000)ln(22/P)
But I am not sure.
oh and we do not know how to find the table on a calculator to figure the minimum rate of interest.
ReplyDeleteDon't worry about the table thing, just do what you know.
ReplyDeleteAs far as #100 goes, I am surprised you didn't discover this when you looked it up online, you maybe didn't know what to look for. In the problem we have two unknowns, T and Po. Obviously, we can't solve if we don't know one of those (since we are solving for T, we need to know Po.
Po is the same universally, it is the Barometric pressure at sea level and is the same world wide. If you look on page 500, you will discover that the book states this to be 76cmHg. And that is what it will always be for all barometric pressure problems. So, just plug 76 in for Po and solve.
THis should make the problem much easier..
P = 22 by the way.
NS