Okay, so sorry I didn't put the post up this week... On problem #96, you are on the right track. Now use the quotient property to make (lnA/25000) = ln A - ln 25000. Then you can figure out what the ln 25000 is and add it to both sides of the equation. Take e^x on both sides to eliminate the ln and you find out what A is!!! The answer of course is NO. You will need to have more than 25,000 to start.
On #100, just plug in 2 for T(Vc) and x for (Vc). Then you will have the following: 2 = 5 ln (25,000/x) Divide both sides by 5 and do the quotient property to get the following: .4 = ln 25,000 - ln x Move ln x to the left and .4 to the right: ln x = ln 25,000 - .4! Solve from there and round to the nearest $250!
on 62 I have
ReplyDelete25(1/5)^3
so for answer a i get .2cm
then for b i have set up 16=25(1/5)t
which gives 16/25 = (1/5)t
i dont know if this is right but if it is then I dont know what to do from here
having problems with word problems on page 503 #96 I have it worked to 1.5=ln(A/25000) what is next.
ReplyDelete#100 I can't fig the second part of the problem
Okay, so sorry I didn't put the post up this week...
ReplyDeleteOn problem #96, you are on the right track.
Now use the quotient property to make (lnA/25000) = ln A - ln 25000.
Then you can figure out what the ln 25000 is and add it to both sides of the equation.
Take e^x on both sides to eliminate the ln and you find out what A is!!!
The answer of course is NO. You will need to have more than 25,000 to start.
Hope this helps
NS
On #100, just plug in 2 for T(Vc) and x for (Vc).
ReplyDeleteThen you will have the following:
2 = 5 ln (25,000/x)
Divide both sides by 5 and do the quotient property to get the following:
.4 = ln 25,000 - ln x
Move ln x to the left and .4 to the right:
ln x = ln 25,000 - .4!
Solve from there and round to the nearest $250!
Hope this helps
NS