You are looking for two consecutive EVEN integers, so you want n+(n+2) NOT n+(n+1)... Set it up like this 12<= n+(n+2) <= 22 (Tip: <= means less than or equal to...) From there, you combine the two n's to make 2n +1 12<=2n+2<=22 Then subtract everything by 2 10<=2n<=20 Now divide the 2 5<=n<=10.
Remember, this is for the first integer ONLY! AND they have to be even So the first integer could be 6, 8, OR 10.
That means the second integer could be 8, 10, OR 12 Final Answer 6 and 8; 8 and 10; 10 and 12
not sure how to set up #98 n+(n+1)>12<22 is this correct.
ReplyDeleteYou are looking for two consecutive EVEN integers, so you want n+(n+2) NOT n+(n+1)...
ReplyDeleteSet it up like this
12<= n+(n+2) <= 22
(Tip: <= means less than or equal to...)
From there, you combine the two n's to make 2n +1
12<=2n+2<=22
Then subtract everything by 2
10<=2n<=20
Now divide the 2
5<=n<=10.
Remember, this is for the first integer ONLY! AND they have to be even
So the first integer could be 6, 8, OR 10.
That means the second integer could be 8, 10, OR 12
Final Answer
6 and 8; 8 and 10; 10 and 12
You were on the right track
NS
In line 5 of the above comment, 2n+1 should read 2n+2 as it does in line 6.... SORRY!
ReplyDelete